N+[n+2]+[n+4]=51

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Solution for N+[n+2]+[n+4]=51 equation:


Simplifying
N + [n + 2] + [n + 4] = 51

Reorder the terms:
N + [2 + n] + [n + 4] = 51

Remove brackets around [2 + n]
N + 2 + n + [n + 4] = 51

Reorder the terms:
N + 2 + n + [4 + n] = 51

Remove brackets around [4 + n]
N + 2 + n + 4 + n = 51

Reorder the terms:
2 + 4 + N + n + n = 51

Combine like terms: 2 + 4 = 6
6 + N + n + n = 51

Combine like terms: n + n = 2n
6 + N + 2n = 51

Solving
6 + N + 2n = 51

Solving for variable 'N'.

Move all terms containing N to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + N + -6 + 2n = 51 + -6

Reorder the terms:
6 + -6 + N + 2n = 51 + -6

Combine like terms: 6 + -6 = 0
0 + N + 2n = 51 + -6
N + 2n = 51 + -6

Combine like terms: 51 + -6 = 45
N + 2n = 45

Add '-2n' to each side of the equation.
N + 2n + -2n = 45 + -2n

Combine like terms: 2n + -2n = 0
N + 0 = 45 + -2n
N = 45 + -2n

Simplifying
N = 45 + -2n

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